A body of mass 2 kg has an initial velocity of 3 ms
only along OX and is subjected to a force of 4 N in
the direction perpendicular to OX as shown in the
figure. The body reaches the point P after 4 s. The
distance OP is
(a) 12 m
(b) 28 m
(C) 24 m
(d) 20 m
Tf the
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Answer:
20
Explanation:
1st cal. dis. in x=4s×3m/s=12
for y=1/2at2=16
then dis=√16²+12²=20
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