Question

A body of mass 2 kg has initial velocity of 3m/s along OE and it is subjected to a force of 4 N in a direction perpendicular to OE. The distance of the body fromance O after 5 sec is

Answer 1

s=ut+1/2ut^2
GIVEN:
u=3,t=5,

F=ma
4=2a
a=2
PUT IN FORMULA
s=40m

Answer 2

Answer:

B

Explanation:

The acceleration of the body perpendicular to OE is a=Fm=42=2m/s2

Displacement along OE , s1=vt=3×4=12m

Displacement perpendicular to OE

s2=12at2=12×2×(4)2=16m

the resultant displacement

s=√s21+s22=√144+256=√400=20m