A body of mass 2 kg, initially at rest, is moved through
3 m along the horizontal by a force of 10 N acting at an
angle of60° with the horizontal. The kinetic energy gained
by the body is
(a) 15 J
(b) 20 J
(c) 25 J
(d) 30 K
Answers
Answered by
1
Answer:
I think it is 20 because formula of ki netik energy is 1/2 m v 2
Answered by
4
Answer:15J
Explanation: m=2kg
U=0
s=3m
F=10N
¤=60^•
F=ma
10=2a
a=5m/s^2
V^2=U^2+2as
V^2=2as
V^2=30 m/s
WD =1/2mv^2*cos¤
=1/2*2*30*1/2
WD=15J
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