Question

A body of mass 2 kg initially at rest moves under the the action of applied force 7N on a table with coefficient of kinetic friction =0.1 . Calculate the kinetic energy or work done in 10 s.

Answer 1

Step-by-step explanation:

moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1. Compute the

(a) work done by the applied force in 10 s.

(b) work done by friction in 10 s,

(c) work done by the net force on the body in 10 s,

(d) change in kinetic energy of the body in 10 s,

and interpret your results.