A body of mass 2 kg intially at rest on a smooth horizontal surface,gets acted by a constant force of 8N Find time taken in seconds by the body to move through distance of 18m
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Answer:
m=2kg
u=0
f=8N
s=18m
t=?
from newton's second law,
f=ma
a=f/m
a=8/2
a=4m^2/s
from kinematic equation,
s=ut +1/2at^2
s=1/2at^2 (u=0)
18=1/2 (4) t^2
t^2=9
t=√9
t=3 s
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