A body of mass 2 kg is acted upon by a force such that its velocity time graph is as shown find the work done by this force
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Answer:
The graph is given between force and time.
Area under Force-time graph gives Impulse.
So, Total area in 20s is
A
2
=
2
1
×5×20
=50m
2
A
1
=20×5=100m
2
A
3
=
2
1
×10×(−20)=−100m
2
Therefore total area A=A
1
+A
2
+A
3
A= 50m
2
Work done W= F×s
=(F×t)×v
Initial velocity is given, v=$$5m/s$$
Work done, W=Ft.v
W= 50 x 5 J
= 250J
Explanation:
hope its help
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