Question

A body of mass 2 kg is at rest 500 joule work is done on the body to raise it to 10 meters what is the speed
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Answer 1

$\boxed{\rm{\orange{Given \longrightarrow }}}$

• Mass of the body = 2k
• Work done by body = 500 J
• Initial velocity = 0 m/s
• Displacement = 10 m

$\boxed{\rm{\green{To\:Find\longrightarrow }}}$

• Speed of the body

$\boxed{\rm{\red{Solution\longrightarrow }}}$

Firstly we have to find Force of the body

$\begin{lgathered}\longrightarrow \: \bf Work = Force\times Displacement \\ \\ \longrightarrow \: \sf 500 = F\times 10 \\ \\\longrightarrow \: \sf F= \frac{500}{10} \\ \\ \longrightarrow \: \sf F = 50 \: N\end{lgathered}$

Now , we have to find acceleration of the body

$\red\bigstar\:\rm{\gray{\overbrace{\underbrace{\green{Force\:=\:mass\times{acceleration}\:}}}}}$

$\begin{lgathered}\longrightarrow \: \sf 50= 2 \times a \\ \\\longrightarrow \: \sf a = \frac{50}{2}\\ \\\longrightarrow \: \sf a = 25 \: {ms}^{ - 2}\end{lgathered}$

Now by using 3rd law of motion we will find velocity of the body

$\orange\bigstar\:\rm{\gray{\overbrace{\underbrace{\pink{{v}^{2} - {u}^{2} = 2as \:}}}}}$

$\begin{lgathered}\longrightarrow\: \sf {v}^{2} - {0}^{2} = 2 \times 25 \times 10 \\ \\ \longrightarrow \: \sf {v}^{2} = 500 \\ \\ \longrightarrow \: \sf v = \sqrt{500} \\ \\\longrightarrow \: \sf v = 100\sqrt{5} {ms}^{ - 1}\end{lgathered}$

Answer 2

Explanation:

20 thanks= 20 thanks

20 thanks= 20 thanks