Question

a body of mass 2 kg is at rest .what should be the magnitude of force which will make the body move with a speed of 30 m/s at the end of 1 sec​

Answer 1

Solution :-

Given ,

• Mass of body = 2kg
• Initially at rest
• Final velocity = 30 m/s
• Time = 1 s

To find ,

• Force acted on the body which the body move at the speed of 30 m/s for 1s

Firstly finding acceleration

Using the first eq of motion

v = u + at

Substituting the known values

→ 30 = 0 + a(1)

→ a = 30 m/s²

Now. finding force using Newton's 2nd law of motion

F = m × a

→ F = 2 × 30

→ Force = 60 N

Hence , force acted on the body = 60 N

Answer 2

Answer:

given: mass=m=2kg

initial velocity=u=0

final velocity=v=30m/s

time=t=1 second

acceleration=a=?

Force=f=?

Step-by-step explanation:

acceleration=v-u/t

a=30-0/1

acceleration=30m/s²

F=m*a

F=2*30

F=60N