Question

.A body of mass 2 Kg is being rotated in a circle by 0.5 m long string, the work done by centripetal force is
​

Answer 1

Answer:

m= 0.2 kg,R = 0.5m and V = 3 m/s

therefore,

$fc = \frac{ {mv}^{2} }{r} = \frac{(0.2)( {0.3)}^{2} }{(0.5)} = 3.6n$

Explanation:

Hope this may help you.....

☬Tanvi☬

✌️ Follow me ✌️