Physics, asked by miftiqar, 1 year ago

A body of mass 2 kg is dropped from a height of 15 m. Calculate the initial momentum and the momentum just before it strikes the ground (g=10m/s*s).

Answers

Answered by Steph0303
28
Hey there !

Solution :

Given :

Mass - 2 kg

Height = 15 m

Gravity - 10 m/s²

Initial Momentum :

Since the Ball is in rest, the initial velocity of the ball will be 0 m / s. Hence we know that,

Initial Momentum = Mass * Initial Velocity ( u ) 

=> Initial Momentum = 2 kg * 0 m / s = 0 kg . m / s

Final Velocity ( v ) = √ ( 2gh )

Final Velocity = √ ( 2 * 10 * 15 )

Final Velocity = √ 300 => 10√3  m / s

Hence Final Momentum = Mass * Final Velocity ( v )

=> Final Momentum = 2 * 10 √ 3 

=> Final Momentum = 20 √ 3 kg . m / s

Hope my answer helped :-)

Answered by ajhak3
1

The final momentum is 20√3 kg

answer

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