A body of mass 2 kg is dropped from a height of 15 m. Calculate the initial momentum and the momentum just before it strikes the ground (g=10m/s*s).
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Answered by
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Hey there !
Solution :
Given :
Mass - 2 kg
Height = 15 m
Gravity - 10 m/s²
Initial Momentum :
Since the Ball is in rest, the initial velocity of the ball will be 0 m / s. Hence we know that,
Initial Momentum = Mass * Initial Velocity ( u )
=> Initial Momentum = 2 kg * 0 m / s = 0 kg . m / s
Final Velocity ( v ) = √ ( 2gh )
Final Velocity = √ ( 2 * 10 * 15 )
Final Velocity = √ 300 => 10√3 m / s
Hence Final Momentum = Mass * Final Velocity ( v )
=> Final Momentum = 2 * 10 √ 3
=> Final Momentum = 20 √ 3 kg . m / s
Hope my answer helped :-)
Solution :
Given :
Mass - 2 kg
Height = 15 m
Gravity - 10 m/s²
Initial Momentum :
Since the Ball is in rest, the initial velocity of the ball will be 0 m / s. Hence we know that,
Initial Momentum = Mass * Initial Velocity ( u )
=> Initial Momentum = 2 kg * 0 m / s = 0 kg . m / s
Final Velocity ( v ) = √ ( 2gh )
Final Velocity = √ ( 2 * 10 * 15 )
Final Velocity = √ 300 => 10√3 m / s
Hence Final Momentum = Mass * Final Velocity ( v )
=> Final Momentum = 2 * 10 √ 3
=> Final Momentum = 20 √ 3 kg . m / s
Hope my answer helped :-)
Answered by
1
The final momentum is 20√3 kg
answer
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