Question

A body of mass 2 kg is dropped from a height of 1m it's kinetic energy as it touches the ground is​

Answer 1

Answer:

The kinetic energy as it touches the ground is 20J

Answer 2

Answer:

19.6 Joules

Step-by-step explanation:

First calculate final velocity.

V^2 = Vi^2 + 2ax

V^2 = 0 + 2(9.8 m/s/s)(1 meter)

V = 4.42 m/s

Now you can calculate kinetic energy.

KE = (0.5)mv^2

KE = (0.5)(2 kg)(4.42 m/s)^2

KE = 4.42^2

KE = 19.6 Joules