A body of mass 2 kg is dropped from a height of 4 m. What is its kinetic energy, when it the ground ? (g = 10 m/s)
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1
Answer:
m=2kg
h=4m
g=10m/s
Here, by conservation of energy, the potential energy of the body at height h is converted into kinetic energy.
Thus,mgh=KE
or KE=2×4×10=80 J
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Answered by
0
Answer:
Here, by conservation of energy, the potential energy of the body at height h is converted into kinetic energy before its strikes the ground.
Thus, mgh=KE
or KE=0.1(10)10=10J
Explanation:
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