a body of mass 2 kg is dropped from a height of 5 M find kinetic energy with which it strikes the ground.take G is equal to 10 M per second square
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By third equation of motion
v *2 - u *2 =2gh
..As u =0{object is at rest when dropped}
●◆◆>v*2=20×5 =100 m
◆◆●●>>v= 10 m/s...
so kinetic energy = 1/2(2)(100)
◆◆◆◆◆◆◆◆●●●>100m/s...
Hope it helps....◆◆◆◆●●●●●●◆◆◆◆
Anonymous:
so bye
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