A body of mass 2 kg is dropped from rest from a height 20 m from the surface of Earth. The body hiys the ground with velocity 10 m/s, then work done (g=10m//s^(2))
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Answer:
400 Nm
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Answer:
The work done is 500J.
Explanation:
The total work done by the body is given as,
(1)
Where,
W=total work done by the body
P.E.=Potential energy
K.E.=Kinetic energy
From the question we have,
The mass of the body(m)=2 kg
The height from which the body is dropped(h)=20m
The velocity with which the body hits the ground(v)=10m/s
The acceleration due to gravity(g)=10m/s²
The kinetic energy(K.E.)
(2)
By inserting variables in equation (2) we get;
(3)
The potential energy(P.E.)
(4)
By inserting variables in equation (4) we get;
(5)
By substituting the values of "K.E." and "P.E." in equation (1) we get;
(6)
Hence, the work done is 500J.
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