A body of mass 2 kg is hung on a spring balance mounted vertically in a lift. If the lift
descends with an acceleration equal to the acceleration due to gravity ‘g’, the reading
on the spring balance will be
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Answer:
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Explanation:
Mass of the body m=2kg
Acceleration of lift in downward direction a=g
Let the reading of spring balance be N.
Equation of motion for the body : ma=mg−N
Or mg=mg−N (∵a=g)
⟹ N=mg−mg=0
Thus the spring balance will show zero reading
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