CBSE BOARD X, asked by vedantsonawanescitec, 1 year ago

A BODY OF MASS 2 KG IS INITIALLY MOVING WITH A VELOCITY OF 4 M/S . NOW A FORCE OF 1.25 N ACTS ON IT IN THE DIRECTION OF INITIAL MOTION FOR 8 SEC . FINAL VELOCITY OF THE BODY IS :
A. 12.5
B. 17
C. 9
D. 25

Answers

Answered by aditya447943
6

u=4m/s

t=8sec

F=1.25N

m=2kg

F=ma

F=m (v-u/t)

1.25=2×(v-4/8)

1.25=v-4/4

v-4=1.25/4

v=5+4=9m/s

Answered by yogeshthoke28
0

Answer:

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Explanation:

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