Question

A body of mass 2 kg is kept at rest.If a force of 5 N is applied on it for 10 s,what will be the work done?​

Answer 1

Answer:

It depends on how long the force is applied.

F=ma → a = F/m = 2 N / 5 kg = 0.4 m/s2

V= at

E = 1/2 m*V^2 = 0.5*5*(0.4*t)^2 = 0.4*t^2

In 1 second 0.4 Joules is expended. In 10 seconds 40 Joules is expended. In 60 seconds 1.44 kJ is expended.

The associated speeds are 0.4 m/s, 4 m/s, and 24 m/s.

Answer 2

Answer:

the answer is zero...........