Question

A body of mass 2 kg is moving along a straight path with the velocity of 2 m/s. The external force acting on the body is _____.
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Answer 1

Answer:

Given that F = i - 2j , we can say that the acceleration will be a = 0.5i - j since a =

m 3

F

and mass is given to be 2kg in this question. After this, we calculate the velocity after breaking initial velocity V = 3i + 4j into its components. Thus, in the x-direction, Vx=u(x)+a(x)* t=3+(0.5*4)=5 m/s .

In the y direction Vy=u(y)+a(y)* t=4-4=0

Therefore we get answer C, which is 5 m/s in the x direction.

Explanation:

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Answer 2

Answer:

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