Question

A body of mass 2 kg is moving at a speed
36 km h-, on a rough horizontal surface. The
minimum distance in which it comes to a stop is
(g = 10 ms?, coefficient of friction = 0.2)​

Answer 1

Answer:

Veocity = 10.m/ sec

s= v^2/ a

it's rolling Friction Force is 0.2 Mg= 0.2x2/10= 0.04

S = 100/ 0.04 = 10000/4= 2500 Meter.