a body of mass 2 kg is moving on a horizontal surface with an initial velocity of 4 m per second comes to rest after 2 seconds what is the nature and magnitude of retarding force acting the body
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Explanation:
mass =2kg
u=4m\s
v=0 (as body comes to rest to rest )
F=ma
=m*{(v-u)/t}
=2*(2/2)
2N (mag )
force acting in opposite direction of motion to bring it to rest
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-4N is the correct answer for this question
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