A body of mass 2 kg is moving on a smooth floor in straight line with a uniform velocity of 10 m/s. Resultant force acting on the body is (in N)
Answers
Answered by
9
Answer : 20 N
Solution :
_________
Given that :
Mass = 2 kg
velocity = 10m/sec
Also given that with uniform velocity so time = 1 sec
From the second law of motion :
![F = \frac{P}{t} \\ \\ = > F = \frac{mv}{t} \\ \\ = > F = \frac{2 \times 10}{1} \\ \\ = > F = 20 F = \frac{P}{t} \\ \\ = > F = \frac{mv}{t} \\ \\ = > F = \frac{2 \times 10}{1} \\ \\ = > F = 20](https://tex.z-dn.net/?f=F+%3D+%5Cfrac%7BP%7D%7Bt%7D+%5C%5C+%5C%5C+%3D+%26gt%3B+F+%3D+%5Cfrac%7Bmv%7D%7Bt%7D+%5C%5C+%5C%5C+%3D+%26gt%3B+F+%3D+%5Cfrac%7B2+%5Ctimes+10%7D%7B1%7D+%5C%5C+%5C%5C+%3D+%26gt%3B+F+%3D+20)
So, the force will be 20 N.
Solution :
_________
Given that :
Mass = 2 kg
velocity = 10m/sec
Also given that with uniform velocity so time = 1 sec
From the second law of motion :
So, the force will be 20 N.
Answered by
4
Answer:
answer is 0
Explanation:
answers is zero because no realative motion acting or friction on smooth floor is less
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