A body of mass 2 kg is moving with a constant velocity of 3 m / s . Calculate the work done on the body.
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Answer:
hope it will help you
Explanation:
Given : m
1
=2kg m
2
=1kg u
1
=3 m/s u
2
=4 m/s
Let the common velocity of the combined body be V
Mass of combined body M=2+1=3kg
Applying conservation of momentum :
2×3−1×4=3×V ⟹V=
3
2
m/s
Momentum of the system P=2×3−1×4=2 kg m/s
Loss in kinetic energy of the system due to collision ΔK.E=K.E
i
−K.E
f
ΔK.E=
2
1
(2)×3
2
+
2
1
(1)×4
2
−
2
1
(3)×(
3
2
)
2
⟹ΔK.E=
3
49
J
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