Question

A body of mass 2 kg is moving with a velocity
of u = 3ỉ +4îm/s. A steady force
F=î-2Î N begins to act on it. After four
seconds, the body will be moving along.
1) X-axis with a velocity of 2 m/s
2) Y-axis with a velocity of 5 m/s
3) X-axis with a velocity of 5 m/s
4) Y-axis with a velocity of2 m/s​

Answer 1

Answer:

Given that F=i-2j, we can say that the acceleration will be a=0.5i-j since a=

m

F

and mass is given to be 2kg in this question. After this, we calculate the velocity after breaking initial velocity V=3i+4j into its components. Thus, in the x-direction, Vx=u(x)+a(x)×t=3+(0.5×4)=5 m/s.

In the y direction,Vy=u(y)+a(y)×t=4−4=0

Therefore we get answer C, which is 5 m/s in the x direction.