Question

A body of mass 2 kg is placed on a horizontal
surface having coefficient of kinetic friction 0.4
and coefficient of static friction 0.5. If a
horizontal force of 25 N is applied on the body,
the frictional force acting on the body will be:
m
(g = 10 )
S​

Answer 1

Answer:

8N

Explanation:

max friction it can apply before moving is (coefficient of static friction)(N)=(0.5)(20)

=10N

so the object would move and it will encounter kinetic friction which equals to=(coefficient of kinetic friction)(N)

=(0.4)(20)=8N