a body of mass 2 kg is placed on a horizontal surface having coefficient of kinetic friction 0.4 and coefficient of static friction will be 0.8 horizontal force 2.5 newton is applied on the body the friction force acting on the body
the minimum force required to slide the body is
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Normal force acting on the body
= mg
= 2×10
= 20 N
Static Frictional Force
= coefficient of static Friction × Normal force
= 0.5×20
= 10 N
as applied force is 2.5 N which is less that static frictional force, hence the body will not move and the frictional force acting on it will be = 2.5 N
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