Question

A body of mass 2 kg is placed on horizontal surface having kinetic friction 0.4 and static friction 0.5 .if the force applied on the body is 2.5N then the frictional force acting on the body will be

Answer 1

Normal force acting on the body
= mg
= 2×10
= 20 N

Static Frictional Force
= coefficient of static Friction × Normal force
= 0.5×20
= 10 N

as applied force is 2.5 N which is less that static frictional force, hence the body will not move and the frictional force acting on it will be = 2.5 N

Answer 2

Normal force acting on the body = 2 x 10 = 20N
Static force = 0.5 x 20 = 10N

The force acting on body is 2.5 N which is less than the frictional force
So force acting on the body = 2.5N