A body of mass 2 kg is placed on horizontal surface having coefficient of kinetic friction 0.4 and static friction 0.5 if horizontal force 2.5 is applied on it, the acceleration is?
14 q and 17 are interlinked try to solve 14 and plz explain me 17 q? urgent
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14.
Minimum force required = Limiting friction
= μN
= μmg
= 0.5 * 2 * 10
= 10 N
17.
Limiting friction = 10 N
External force = 10 N
Net force = 0
Acceleration = 0
If net force is 0 then it means body is moving with constant velocity (a = 0).
No option is correct. Sometime it happens.
Minimum force required = Limiting friction
= μN
= μmg
= 0.5 * 2 * 10
= 10 N
17.
Limiting friction = 10 N
External force = 10 N
Net force = 0
Acceleration = 0
If net force is 0 then it means body is moving with constant velocity (a = 0).
No option is correct. Sometime it happens.
NithinSaisun:
thank u
You’re welcome :)
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0
Question 14 that is 10 N
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