A body of mass 2 kg is placed on smooth horizontal plane, pulled by the force of 2 n then the velocity of the body after 3 s is
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Answer:
Step-by-step explanation:
as per given data
F= 5N , m= 2kg,
and according to Newton's laws
net force,F=ma
a=F/m=5/2=2.5 m/s sq.
S=ut+ 1/2at^2
where s is displacement
so, s= 0+0.5 * 2.5* 25=31.25
and, work = force * displacement
=5* 31.25
=156.25 joules
Hope it helps you...
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