Question

) A body of mass 2 kg is thrown up at a velocity of 10 m/s. Find the potential energy at the highest point.

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Answer 1

Question: A body of mass 2 kg is thrown up at a velocity of 10 m/s. Find the potential energy at the highest point.

Given that :-

• Mass of the body = 2 kg
• Initial velocity = 10 m/s
• Final velocity = 0 m/s (∵ it is at highest point).

To find :-

• The potential energy at the highest point.

Solution :-

• The potential energy at the highest point = 99.96 J

Using concepts :-

• 3rd law of motion equation.
• Formula to find potential energy.

Using formulas :-

• 3rd law of motion equation => v²-u² = 2as.
• Formula to find potential energy => mgh.

Where,

• v denotes final velocity.
• u denotes initial velocity.
• ² denotes square.
• a denotes acceleration.
• s denotes displacement or it is also known as distance.
• m denotes mass of the body.
• g denotes acceleration due to the gravity.
• h denotes height.

Full solution :-

~ Firstly let us find the height by using the 3rd equation of motion..!

↝ v²-u² = 2as.

↝ 0² - 10² = 2(9.8)(s)

↝ 0 - 100 = 2 × 9.8 × s

↝ -100 = 19.6 × s

↝ -100 = 19.6s

↝ -100/19.6 = s

↝ -5.10 = s

↝ s = -5.10 m

• Henceforth, height is -5.10 metres. We can't take in (-) negative henceforth, height is 5.10 metres.

~ Now let's find the potential energy..!

↝ P.E = mgh

↝ P.E = 2(9.8)(5.10)

↝ P.E = 2 × 9.8 × 5.10

↝ P.E = 19.6 × 5.10

↝ P.E = 99.96 J

• Henceforth, 99.96 J is the potential energy

Answer 2

Answer:

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