A body of mass 2 kg is thrown up vertically with a kinetic energy 490J.If the acceleration due to gravity is 9.8m/s2, the height at which the kinetic energy of the body becomes half of original value is a)50m b)25m c)12.5 d)10
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energy conservation
K1-K2 =mgh
490-490/2=2×9.8×h
490-245=19.6h
245=19.6h
h =245/19.6
h =12.5 m
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