a body of mass 2 kg is thrown up with a speed of 25 m/s find its maximum kinetic energy
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K.E. =¹/² ×m×v²
= ¹/² × 2 × 25×25
= 625 Joules
Answered by
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K(E) =1/2mv^2
=1/2×2×25×25j
= 625j is the maximum K(E.)
=1/2×2×25×25j
= 625j is the maximum K(E.)
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