Question

a body of mass 2 kg is thrown up with a velocity of 10 M per second find the kinetic energy of the body at the time of thro also find the potential energy of the body at the highest point the value of g is equals to 10 M per second

Answer 1

$<b>$Given,

m=2 kg

Initial velocity, u=10 m/s

Kinetic energy will be given by

$K=\frac{1}{2}mv^2$

=1/2×2×102=100 JNow,g=10m/s

At highest point,

 v=0

Using relation,

v^2-u^2=2gh

0−100=2 ×(−10)

=5 m

Potential energy, P=mgh=2×10×5=100J

$<marquee>$

thank you

Answer 2

Mass of object=2kg

Velocity of object is 10m/s

Value of G will be= -10m/s^2

 v-u/t=a

 10-0/t=10

  10t = 10

    t=1 sec

Displacement= v*t=10*1=10m  

Kinetic Energy=1/2mv^2 = 1/2 * 10 * 100 =500J

Potential Energy = mgh = 10* -10 *10 = -1000J