Question

A body of mass 2 kg is thrown up with a velocity of 25m/s find max potential energy

Answer 1

Mass = 2kg

Initial velocity, u = 25 m/s

Final velocity, v = 0

Initial kinetic energy = $\frac{1}{2} mv^{2}$

                                  = $\frac{1}{2} *2* 25*25$

                                  = 625 J

At the top most point since velocity is 0 ∴ Kinetic energy is 0

But according to law of conservation of energy since this energy cannot be lost, it is converted into potential energy at a maximum height

∴ Potential energy at max height = Kinetic energy at the lowest point = 625 J

In case you want to find the height use the formula

potential energy = mgh

potential energy/mg = h

and substitute potential energy, mass and gravitational acceleration with 625 J, 2 kg and 9.8 or 10 m/s²

Answer 2

Answer:

625 J.

Explanation:

Maximum kinetic energy of the body = Maximum potential energy of the body.  

Given,  Mass of the body, m = 2 kg

            Speed, v = 25 m/s

Therefore, K.E. = 1 /2 mv2  = 1/2 × 2 × 25 × 25  = 625 J.

hence,P.E.=625 J.