Physics, asked by adityaay, 11 months ago

a body of mass 2 kg is thrown up with a velocity of 30 metre per second find the potential energy of the body at the highest point.​

Answers

Answered by sophysherry
2

Answer:

mass = 2kg = 2000g

g(gravity) =9.8m/s

height = 30m/s

potential energy = mgh

= 2000×9.8×30

= 60000 × 9.8

= 588000

I am not sure about this answer.

Answered by Anonymous
8

\large\underline{\underline{\sf Given:}}

  • Mass of body (m) = 2kg

  • Initial Velocity (u) = 30m/s

  • Final Velocity (v) = 0m/s (At highest point )

  • g = -10m/s²

\large\underline{\underline{\sf To\:Find:}}

  • Potential Energy at highest point (PE) = ?

\large\underline{\underline{\sf Solution:}}

According to third equation of motion .

\large{\boxed{\sf v^2=u^2-2gs}}

\large\implies{\sf 0=(30)^2-2×10×s }

\large\implies{\sf 0= 900-20s}

\large\implies{\sf s=\frac{900}{20}}

\large\implies{\sf s=45m}

•°• Maximum Height at which body goes is 45m

We know that Potential Energy at highest point is :

\large{\boxed{\sf PE=mgh }}

\large\implies{\sf PE=2×10×45 }

\large\implies{\sf PE=900J}

\large\underline{\underline{\sf Answer:}}

•°•Potential Energy at the highest point is 900J

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