a body of mass 2 kg moves in a circular path of radius 1 metre with a constant speed of 5 M per second calculate work done by the body in negotiating a quarter circle
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body of mass 2 kg moves in a circular path of radius 1 m with a constant speed of 5 metre per second calculate work done by the body in negotiating a quarter circle change in kinetic energy of the body in moving this distance
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Circumference of circle = 2*22/7*1
Quarter = 1/4*2*22/7*1
Work done = F *S
= (5*2)*11/7
=110/7J
= 15.71J
Quarter = 1/4*2*22/7*1
Work done = F *S
= (5*2)*11/7
=110/7J
= 15.71J
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