Question

a body of mass 2 kg moving with a speed of 100m per second hits a wall and rebounds with same speed if the contact time is 1÷50 second the force applied on the wall is

Answer 1

Initial v = 0m/sec^2
final velocity =100m/sec^2
a = 100÷1/50= 5000m/sec^2
F = m× a
= 2kg × 5000m/sec^2
= 10000kg m/ sec^2
=10000N