Question

A body of mass 2 kg moving with a velocity of 3 m/s collides head on with a body of mass 1kg moving in the opposite direction with a velocity 4 m/s. After the collision, two bodies stick together and move with a common velocity of K/3 m/s, find the value of K.

Include a detailed explanation

Answer 1

Answer:

Value of K is 10m/s

Given

$Mass \: of \: the \: body (m1) = 2kg \:$

$Initial \: vel(u1) = 3m/s$

$Mass \: of \: the \: body (m2)= 1kg$

$Initial \: vel(u2) = 4m/s$

$Final vel of both the bodies = \frac{K}{3} m/s$

To find the value of K

Explanation:

$A/T \: law \: of \: conservation \: of \: momentum,$

$(m1 \times m2) +( m2 \times u2) = (m1 + m2) \times \frac{K}{3}$

$= > (2 \times 3) + (1 \times 4) = (2 + 1) \times \frac{K}{3}$

$= > 6 + 4 = 3 \times \frac{K}{3}$

$= > 10 = K$

$= > K = 10$

Hope this will help u.....