Question

A body of mass 2 kg moving with velocity of 6 m/s strikes in elastically with another body of same
mass mass at rest. The amount of heat evolved during collision is
(a) 18 J (b) 36 J (c) 9 J (d) 3 J

Answer 1

Answer:

$18j$

Explanation:

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Answer 2

The amount of heat evolved during collision is 18 Joules.

Explanation:

It is given that,

Mass of both the body, m = 2 kg

Speed of the body, v = 6 m/s

Another body is at rest, v' = 0

We need to find the amount of heat evolved during collision. It is equal to loss in energy. It is given by :

$E=\dfrac{1}{2}\dfrac{m_1m_2}{m_1+m_2}(v'-v)^2$

On substituting all the values in above formula we get :

$E=\dfrac{1}{2}\times \dfrac{2\times 2}{2+2}\times (6)^2$

E = 18 Joules

So, the amount of heat evolved during collision is 18 Joules. Hence, the correct option is (a).

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