A body of mass 2 kg slides down with an acceleration of 3 m/s2 on a rough inclined plane having a slope of 30. The external force required to take the same body up the plane with the same acceleration will be :
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(f)= Kmgcos30=1/1.73 * 1.73/2 * 20 = 10 N
mgsin30=2*10*1/2=10 N
m=2kg
a=3m/s^2
So F + Kmgcos30 − mgsin30 = ma
putting values
F + 10 − 10 = 2 * 3
F = 6 N
Hence required force to get an acceleration of 3m/s^2 in upward drection is 6 N.
mgsin30=2*10*1/2=10 N
m=2kg
a=3m/s^2
So F + Kmgcos30 − mgsin30 = ma
putting values
F + 10 − 10 = 2 * 3
F = 6 N
Hence required force to get an acceleration of 3m/s^2 in upward drection is 6 N.
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