Question

A body of mass 2 kilogram is kept at rest. if a force of 5 n is applied on it for 10 seconds. what will be the work done?

Answer 1

Answer :-

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$\tt \: 625 \: \: j$

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m = 2 kg

F = 5 N

t = 10 s

u = 0 m/s

$\implies \bf \: w = \frac{1}{2} mv {}^{2} - \frac{1}{2} mu {}^{2}$

F = ma

$\implies \bf \: a = \frac{f}{m} = \frac{5}{2} = 2.5ms {}^{2}$

On substituting these values in the equation, v = u+ at

v = 0 + 2.5 ×10= 25 m/s

$\implies\bf \: w = \frac{1}{2} mv {}^{2} - \frac{1}{2} mu {}^{2}$

,

$\implies\bf \: \frac{1}{2} \times 2 \times 25 \times 25 - 0$

$\bf \: = \frac{1}{2} \times 2 \times 625$

$\implies\bf \: 625 \: \: j$