Question

a body of mass 20 kg is at rest a force of 5 newton is applied on it the work done in the first second will be
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Answer 1

Answer:

HOPE THE ATTACHMENT HELPS YOU

Answer 2

Answer:

1.25joule

Step-by-step explanation:

m=20kg, F=5N, t= 1 sec

F=ma

5= 20 × a

a= 1/4

we know that,

a=v/t

v= a × t

v= 1/4× 1

v =1/4 m/sec

v=d/t

d=v× t

d= 1/4 × 1

d= 1/4 meter

now we know that

w= f× d

w= 5× 1/4

w= 5/4 =1.25joule