Question

a body of mass 20 kg is at rest the force applied on it is fine then find the work done the first second​

Answer 1

Answer:

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Explanation:

Given force = 5N

mass of the body = 20 kg

then acceleration produced in the body=force applied/mass of the body =5/20=1/4 m/s^2

using second equation of motion = s=ut+1at^2/2

distance travelled in three seconds :

s = 1 x 1 x 3 x 3 /8=1.125 m

then work done = force x distance

workdone= 5 x 1.125=5.625 joule.