Question

a body of mass 20 kg is dropped from a height of 50 m. calculate the kinetic energy of the body just before it touches the ground. what is this speed at this instant? g=10m/s​

Answer 1

Answer:

1,962 joules

Explanation:

When it’s still at the height of 10m, the object has potential energy. The formula for this is Mass x Gravitational Acceleration x Height. (m*g*h)

Mass = 20 kg

Gravitational Acceleration = 9.81 meters/(second^2)

Height = 10m

Multiplying, we get: 20 x 9.81 x 10 x (kg*meters/(second^2)) * meters

Simplifying: Potential energy = 1,962 Newton * meters = 1,962 Joules

If the object falls 10m to the ground, then right before it hits, all of its potential energy will have been converted into kinetic energy (plus a tiny bit of air friction energy lost in heat). So the kinetic energy will be 1,962 Joules *m...(more)