Question

a body of mass 20 kg is initiall at rest A force is applied on it for 10 N and the body acquires a velocity of 30m/s at the end of 10 Sec
Determine the force
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Answer 1

Answer:

Given, mass of the body, m=5kg;

Initial velocity of the body, u=0;

Force acting on the body, F=20N;

Time for which the force acts, t=10s

If a is the acceleration produced in the body,

a= mm = 520 =4m/s 2

Let v be the velocity of the body after 10 s.

Clearly, v=u+at=0+(4)×(10)=40m/s

Kinetic energy acquired by the body,

E k = 21 mv 2 = 21

(5)×(40) 2 =4000J

Answer 2

Mark as best answer

Answer:

20N

Explanation:

Mass of Body = 20 Kg

• Acceleration = 3 m/s^2

• Force = 80 N

If we calculate the force from this information then F' = 20 × 3 = 60 N . ( force which accelerated the body )

But the given force is 80 N .

Then the Frictional Force acting on the body is

Fr = F' - F = 80 - 60 = 20 N

Frictional Force => 20 N .

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