Question

A body of mass 20 Kg is initially at rest . A force of 80 N is applied on the body then the acceleration is 3m/s^2 , force of friction acting on the body is .

Answer 1

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Given in The question :-

• Mass of Body = 20 Kg
• Acceleration = 3 m/s^2
• Force = 80 N

If we calculate the force from this information then F' = 20 × 3 = 60 N . ( force which accelerated the body )

But the given force is 80 N .

Then the Frictional Force acting on the body is


Fr = F' - F = 80 - 60 = 20 N

Frictional Force => 20 N .


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Answer 2

Acceleration = Net Force / Mass
a = (F - f)/m

3 m/s² = (80 N - f) / (20 kg)

80 N - f = 60 N

f = 80 N - 60 N

f = 20 N

∴ Friction acting on it is 20 N