Question

- A body of mass 20 kg is kept initiaily at rest. A force of
80 N is applied on the body then the acceleration
produced in the body is 3 m/s2, force of friction acting
on the body is :​

Answer 1

Answer

20 Newtons.

$\rule{200}2$

Solution

Given :

mass of body = 20 kg.

External force on the body = 80 N

Acceleration produced = 3 m/s²

To Find

Force of friction on the body.

Let the force of friction be 'f'

From Newton's second law of motion, we know that -

$\sf F_{net} = ma$

Where, $\sf F_{net}$ is the net force on the body, m is mass and a is acceleration produced in the body.

Now, the net force on the given body will be 80 - f

Now, putting the values in equation :

80 - f = 20 × 3

→ 80 - f = 60

→ f = 80 - 60

→ f = 20 N

Hence, the friction force acting on the body is 20 N.

Answer 2

Explanation:

Hey mate

Refers with attachment