A body of mass 20 kg is moving with a velocity of 72 km/h.A force is applied to the body for 25 seconds and it attains a veocity of 144km/h.what is the force applied
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F=ma
given, m=20kg a=(u =72×5/18=20 v=144×5/18=40 t=25sec) (v -u) /t=(40-20)/25= 20/25=4/5
F=ma
F=20×4/5
F=16N
given, m=20kg a=(u =72×5/18=20 v=144×5/18=40 t=25sec) (v -u) /t=(40-20)/25= 20/25=4/5
F=ma
F=20×4/5
F=16N
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