Question

A body of mass 20 kg moves with an accleration of 2m per second- 2 the ratevof change of momentum in si unit is

Answer 1

★Answer :-

40 N

★ Given :-

• Mass of the body is 20 kg
• Acceleration of the body is 2m/s²

★To find :-

• Rate of change in momentum

★ EXPLANATION :-

As we know that Rate of change of momentum is given by

Rate of change of momentum = mv-mu/t

Rate of change of momentum = m(v-u) /t

They given that Acceleration of the body is 2 m/s²

We also know that ,

Acceleration is defined as Change in velocity per unit time is called acceleration

a = change in velocity/Time

a = (v-u)/t

So,

2 = (v-u)/t

Now,

Rate of change of momentum = m(v-u) /t

= 20(2)

= 40 N

So, the rate of change of momentum is 40N

═══════════

★ Know more :-

Momentum is defined as product of mass and velocity

Momentum = mass × velocity

P = mv

Change of momentum = m ( change in velocity)

Change in momentum = m(v-u)

Rate of change in momentum = m(v-u)/t