Question

A body of mass 20 kg moving with a speed of 10 ms -1 on a horizontal smooth surface
collides with a massless spring of spring constant 5 N/m. If the mass stops after
collision, distance of compression of the spring will be :
(a)
10 m
(b)
50 m
(c)
5 m
(d)
20 m​

Answer 1

Answer:d 20

Explanation

Law of Mechanical energy conservation

1/2mv^2=1/2kx^2

20X 100/2=1/2X 5X x^2

x=20