Question

A body of mass 20 kg moving with a velocity of 10 ms −1 collides with another body of mass 40 kg moving In the same direction with a velocity of 5 ms −1 .

if heavier body moves with speed 8m/s opposite to the lighter body after the collision . find the velocity of lighter body after collision ?​

Answer 1

Explanation:

m

1

=1kgu

1

=4m/s

m

2

=2kgu

2

=?

using principal of linear momentum conservation:-

m

1

u

1

=m

2

u

2

1×4=2×u

2

u

2

=2m/s